Tennis String Tension Meter

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Tennis String Tension Meter

Physics HW help- (Elasticity) keep getting wrong answer-?


This is the question I need answered:
A nylon tennis string on a racket is under a tension of 240 N. If its diameter is 0.93 mm, by how much is it lengthened from its untensioned length of 30.4 cm

Here is my attempt to solve (but I get the same WRONG answer everytime)------------------------------…
Everything was converted to meters if needed:
F= 240 N
radius= .000465 m
original length= .304 m
modulus (E)= 5 x 10^9
Area= pi(r^2)= .000000679 m
I have used these equations:
delta L = [(1/E) x (F/A) x Lo]
Lo being Length knot OR initial length
F= E (delta L / Lo) A

No matter what I do, the answer comes out to be .02149 m
The answer needs to be in centimeters, so I end up with .0002149 cm
But it is wrong...
Are my calculations off? Not doing it right? Help please!!!
PLEASE help only if you know the answer and HOW to do it, please and thanks :)

Actually, 0.02149 m is 2.140 cm
lol

You're work looks right to me. I got the same result.
E = (F/A) / (delta L / Lo)
delta L = FLo / AE = 0.02149 m



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Lec 7 | 8.01 Physics I: Classical Mechanics, Fall 1999

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